algebra precalculus - Factorize $ (x+1) (x+2) (x+3) (x+6)- 3x^2 ...
Aug 9, 2013 · Factorize : $$ (x+1) (x+2) (x+3) (x+6)- 3x^2$$ I don't really know where to start, but I expanded everything to get : $$x^4 + 12x^3 + 44x^2 + 72x + 36$$ I used rational roots test …
Prove $ x^n-1= (x-1) (x^ {n-1}+x^ {n-2}+\dots+x+1)$
Aug 17, 2014 · My base case is when $n=2$ we have on the left side of the equation $x^2-1$ and on the right side: $ (x-1) (x+1)$ which when distributed is $x^2-1$. So my base case holds.
algebra precalculus - Factoring $ (x+1) (x+2) (x+3) (x+4)+1 ...
Aug 25, 2014 · If you can pretend you "guessed" the factorization, notice $ (x^2+5x+5)^2-1$ is a difference of squares.
"x += 1" vs "x = x + 1" : r/learnpython - Reddit
Apr 16, 2020 · I honestly don't understand how this expression can be mathematically correct. I always end up writing x=+1 by accident because the correct way of writing seems so …
Derivative of $e^ {x+1}$ - Mathematics Stack Exchange
Aug 16, 2016 · How did you get your answer? Did you try to apply the chain rule? You might get better answers if you show your process so we can point out where things go wrong.
geometry - How to find coordinates of reflected point?
18 Find line perpendicular to $ 2y=x+1$ which passes through $ (3, -3)$ Find intersection point of those two lines ( Foot of perpendicular ) Use Mid-Point Formula (special case of Section …
Verify $(y-x)y' = y-x+8$ has an explicit solution $y = x+ 4 …
Jan 26, 2017 · Ive solved this problem and both sides of the function don't appear to be equal to me. However the solution in the back of the book says it is a solution. Am I not simplifying …
Prove inequality using mean value theorem 1/(x+1) < ln(x+1)
Feb 7, 2022 · Closed 3 years ago. Using the mean value theorem of lagrange I need to prove that for all x > 0: $$ \frac {1} {x+1} < ln (x+1) - ln (x) < \frac {1} {x} $$
calculus - How to determine if a function is one-to-one?
I am looking for the "best" way to determine whether a function is one-to-one, either algebraically or with calculus. I know a common, yet arguably unreliable method for determining this answer …
Radical equation $\sqrt {x+1}+\sqrt {x-1}-\sqrt {x^2 -1}=x$
May 18, 2016 · Only thing I can take from this is that $x^2 -1= (x+1) (x-1)$, but I don't think that would help in any way. I know the answer, but I don't know how to use that to work backwards.